This is a algebra word problem
in Algebra 1 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Best answer
let x be no. of motorbikes and y be no. of cars. We know that cars have 4 tyres each and motorbikes each has 2 tyres. we form simultaneous equations as follows; x+y=94......(1) 2x+4y=310......(2) solving them simultaneously we have, x=94-y substituting this in eqn 2; 2(94-y)+4y=310 =>188-2y+4y=310; 2y=122; y=61 x=94-61; x=33 Thus we have 33 motorbikes and 61 cars. Hint: vehicles(cars + motorbikes)
by Level 2 User (1.9k points)
edited by

Related questions

0 answers
1 answer
asked Jan 31, 2015 in Statistics Answers by anonymous | 746 views
1 answer
asked Jan 22, 2012 in Statistics Answers by anonymous | 1.3k views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
731,953 users