pls answer this question for me.
http://www.mathhomeworkanswers.org/?qa=blob&qa_blobid=901044281887730953
The figure shows a circle with two triangles inscribed, using the diameter
of the circle as the hypotenuse of each triangle. We know that such a triangle
is a right-triangle, which means that angle ACB is 90 degrees. We are given
that angle CAB is 30 degrees, leaving 60 degrees for angle CBA.
Further, we are told that angle CBA is split into two equal parts: angle ABX equals
angle CBX. Therefore, angle ABX is 30 degrees. Angle AXB is another right-angle.
From that we deduce that angle XAB is 60 degrees. Subtracting the 30 degrees
of angle CAB, that leaves us with 30 degrees for angle CAX.