solve x^x^x=2

find the solution set of the exponintial equation: x^x^x=2
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1 Answer

Given x^x^x=2

Take log on both side

log x^x^x=log 2

x^x log x=0.693

Solve for x

x=1.476616

Get free help for Exponential Function Equation

by Level 8 User (30.1k points)

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