Assuming that the only coins available are cents, nickels, dimes and quarters and there are no dollar bills, we can break down $2.18. One way to solve the problem is to split the dollars and cents as two separate packages. First the dollars: 8q (8 coins); 7q+2d+1n (10 coins); 7q+1d+3n (11 coins); 7q+1d+2n+5c (15 coins); 7q+1d+1n+10c (19 coins); 6q+4d+2n (12 coins); 6q+4d+1n+5c (16 coins); 6q+3d+4n (13 coins); 6q+3d+3n+5c (17 coins); 6q+2d+5n+5c (18 coins); 6q+2d+6n (14 coins); 6q+2d+5n+5c (18 coins); 5q+where q, d, n and c are the denominations quarter, dime, nickel and cent. Now the cents: 1d+1n+3c (5 coins); 1d+8c (9 coins); 3n+3c (6 coins); 2n+8c (10 coins); 1n+13c (14 coins). The dollars can be made up from 8, 10-17 coins, which means that the cents must add up to 6-13 or 15 so that 23 coins are accounted for. There are values 6, 9 and 10 within the set of coin totals for 18 cents. So there appear to be at least 3 ways to make up $2.18: 6q+3d+3n+5c+3n+3c=6q+3d+6n+8c=$1.50+0.30+0.30+0.08=$2.18. The other two ways add up to the same denomination totals of 6 quarters, 3 dimes, 6 nickels and 8 cents.