finding the inverse
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Raise each side of the equation as a power of e: e^h=(x+1)/(x-8). Multiply both sides by (x-8): xe^h-8e^h=x+1. Bring the x terms over to the left and other terms to the right: xe^h-x=8e^h+1. Factorise the left: x(e^h-1)=8e^h+1, now divide by (e^h-1) on both sides: x=(8e^h+1)/(e^h-1). This is the inverse equation where x is expressed in terms of h. I assumed the log meant natural log. If it didn't then e should be replaced by the relevant base (e.g., 10).

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