find the maximum number of zeros and Descarte's rule of signs to determine how many positive and negative zeros the function has.  Show work
in Calculus Answers by Level 1 User (780 points)

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1 Answer

f(x) = 5x^4 - 10x^3 + x^2 - 2.5x + 20

because it is to the 4th power there are up to 4 roots.

by Descarte's there are 4 changes from positive to negative.  So there up to 4 real roots and 2 maybe real and 2 complex.

So, there may be 0 to 4 real roots.

2 maybe complex.

f(-x) = 5(-x)^4 - 10(-x)^3 + (-x)^2 - 2.5(-x) + 20

f(-x) = 5x^4 + 10x^3 + x^2 + 2.5x + 20

there are no negative roots

 

by Level 10 User (55.7k points)
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