y=x^2-4 (find x and y intercepts, vertex and axis) I have the answer, but do not know how to work the problem

Question

not sure how to work the problems out with parabola

Answer 1

You can do this a few different ways. You can graph it on a graphing calculator and use the trace function to find the intercepts.  If you don't have a calculator you can plug in points for y and then solve for x.  You know that this is a parabola because of the x^2.  There are going to be 2 x values because you will have to take the square root.

Let's take the example of setting y=0 which will also give us the x intercepts

Plug that in and solve for x

0=x^2-4

add 4 to both sides

4=x^2

take the square root of both sides

x=+2 and -2

so you have two points 0,2 and 0,-2

Now to find the y intercept you plug in 0 for x and solve for y

y=0^2-4

y=-4

you now have a 3rd point -4,0 which is the y intercept.  You can draw the graph with that and see that the parabola is split by the y axis with a vertex at -4,0.

Here is the graph.
 

 

 

 

 

Answer 2

if p varies inversely as the square root of q, and p=12 when q=36, find p when q=16.

Answer 3

 

y = x

2

 + 4x + 3 

Answer 4

SOLUE THE EQUATION BY FIRST CLEARING THE FRACTION: 2/9w=1+1/6w the what is the answer

Answer 5

I need the work shown for this problem.... The students going on Service Adventure had a 2,367-kilometer flight.  If their travel time was 2 hours and 56 minutes, what was their average speed in kilometers per hour?