This is mixed problem solving in chapter 6 of the Mcdougal Littel Algebra and Trig structure and method book 2.
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A boat traveled 36 km downstream in 2 h. return trip upstream=3 h. Find rate of current.

Time multiplied by speed equals distance, which is the same both ways. Boad speed
is s, speed of current is c.

Downstream:
2 hr * (s + c) km/hr = 36 km
(s + c) km/hr = 18 km/hr

Upstream:
3 hr * (s - c) km/hr = 36 km
(s - c) km/hr = 12 km/hr

Add the two equations:

s + c = 18 km/hr
s -  c = 12 km/hr
2s     = 30 km/hr

2s = 30 km/hr
s = 15 km/hr     the boat's speed

Substitute into equation:
s + c = 18 km/hr
15 km/hr + c = 18 km/hr
c = 18 km/hr - 15 km/hr
c = 3 km/hr             the speed of the current
by Level 11 User (78.4k points)

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