Question from implicit function, find dy/dx when, x sin 2y = y cos 2x
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1 Answer

Differentiate wrt x:

2xcos2ydy/dx+sin2y=-2ysin2x+cos2xdy/dx.

dy/dx(2xcos2y-cos2x)=-2ysin2x-sin2y.

dy/dx=(2ysin2x+sin2y)/(cos2x-2xcosy).
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