8th Grade Math Problems

Question

Question : The sum of two numbers is 13. If two times one of these numbers exceeds three times the other number by 1, find the numbers.

Answer 1

This is also a repeet from 2 or 3 daes ago

x+y=13    so y=13-x

2y=3x+1

2(13-x)=3x+1

-2x +26=3x+1

3x+2x=26-1

5x=25

x=5

y=13-x=13-5=8

Answer 2

Solution:

 

Let the numbers be x and y

 

The sum of numbers = 13

 

=> x + y = 13                 ...............(1)

and

2x - 3y = 1                    .................(2)

 

Step 2:

(1) => y = 13 - x

 

Step 3:

 

Put y = 13 - x in equation (2)

 

=> 2x - 3(13 - x) = 1

 

=> 2x - 39 + 3x = 1

 

=> 5x = 40

 

=> x = 8

 

Step 4:

Put x = 8 in equation(1)

 

=> 8 + y = 13

 

=> y = 13 - 8 = 5

 

Hence numbers are 8 and 5.

 

Once you get the answer to your Eighth Grade problem, you should always go back and recheck. Sometimes, you might miss out on small details and going over the problem and solution again helps.