Question : Aline is 10 years older than Alica. In 12 years, the sum of their ages will be 40. How old are Aline and Alice now ?
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2 Answers

y=x+10

(x+12) +(y+12)=40

x+12 +(x+10+12)=40

2x +34=40

2x=6

x=3

y=13

#### 12 yrs later...15+25=40
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Solution:
 
Let Alica's age be represented with x and Aline's age represented with x + 10.
 
In 12 years:
 
Add 12 to both ages 
 
Alica's age = x + 12 and Aline's age = (x + 10) + 12 = x + 22
 
The sum of their ages in 12 years will be 40, so the equation is as follows:
 
=> x + 12 + x + 22 = 40
 
=> 2x + 34 = 40
 
=> 2x = 40 - 34 = 6
 
or x = 6/2 = 3
 
So Alica is 3, and Aline is 13 (i.e. 3 + 10).
 
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