Question : The sum of two numbers is 13. If two times one of these numbers exceeds three times the other number by 1, find the numbers.
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2 Answers

1....x+y=13   or y=13-x

2...2x=3y+1

2x=3*(13-x) +1

2x=-3x +39+1

5x=40

x=8

y=13-x=5

##### chek...2x=16.....3y+1=15+1=16
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Solution:
 
Let the numbers be x and y
 
The sum of numbers = 13
 
=> x + y = 13                 ...............(1)
and
2x - 3y = 1                    .................(2)
 
Step 2:
(1) => y = 13 - x
 
Step 3:
 
Put y = 13 - x in equation (2)
 
=> 2x - 3(13 - x) = 1
 
=> 2x - 39 + 3x = 1
 
=> 5x = 40
 
=> x = 8
 
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