(x+3) 3 solve using distributive method

i have an assignment and i don't what to do?....can you help me by answering it...and please explain so i can understand it...

 

 

tnx...!yes

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I'm guessing that you mean (x+3)3.

We can write this as (x+3)(x+3)(x+3).

Take the first pair of factors and use the distributive property to expand them:

(x+3)(x+3)=x(x+3)+3(x+3)=x2+3x+3x+9=x2+6x+9.

Now (x+3)(x2+6x+9)=x(x2+6x+9)+3(x2+6x+9)=x3+6x2+9x+3x2+18x+27.

So (x+3)3=x3+6x2+9x+3x2+18x+27=x3+9x2+27x+27.

by Top Rated User (1.2m points)

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