If x=√102−10, what is the value of x2/1−10x

number theory and algebra
in Algebra 2 Answers by Level 1 User (120 points)

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1 Answer

x2=102-20√102+100=202-20√102;

1-10x=1-10√102+100=101-10√102=½(202-20√102);

x2/(1-10x)=(202-20√102)/(101-10√102)=2.

by Top Rated User (1.2m points)

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