x2+1/x2=51 find value of x

9th standard s.chand
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2 Answers

me assume that stuf spozed tu be... x^2 +(1/x^2) =51... x^4 +1 -51x^2=0... let x^2=y, then yu hav y^2 -51y +1=0... quadratik equashun giv roots: y=50.9803846 or 0.0196154... so x=+- sqrt av em 2 numbers
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under root 53+7/2
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