In the equation x^3 + rx^2 + sx + t =0 where r,s,and t are integers and 3i and -3i are roots, tell whether the statement is never, always, or sometimes true.
in Algebra 2 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

If 3i and -3i are roots then (x-3i)(x+3i)=x^2+9 is a factor. The remaining factor is x+a, say, so (x^2+9)*(x+a)=x^3+9x+ax^2+9a, and this is equal to x^3+rx^2+sx+t. So a=r and s=9, and t=9a=9r and therefore r and t are related and s=9. You could also say t=rs, so all three are related, although s must equal 9. The statement is true sometimes, and only when the conditions s=9 and t=rs apply.

by Top Rated User (1.2m points)

Related questions

1 answer
asked Apr 30, 2014 in Algebra 2 Answers by Afton | 589 views
1 answer
asked Jan 31, 2013 in Calculus Answers by anonymous | 775 views
1 answer
1 answer
1 answer
asked Feb 29, 2020 by ttttttbwi Level 1 User (280 points) | 916 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
732,218 users