using three basic operations  + , - and X without using a number twice?

how do  you get 385 using  the numbers 7,4,2,10,6, and 8

and 397 using 8,100,50,6,8 and 5 same rules

and 148 using 50,7,7,1,4 and 3

and 839 using 1,75,3,4,5 and 7

and 882 using 5,4,100,9,1 and 8

and 524 using 10,3,100,3,2 and 5
in order of operations by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

-7+4+(2*10)^-(6-8)=397

7(6-8/4^2)*10=385

8(100-50)-(6+5-8)=397

50(4-1)+7/7-3=148

75(7+4)+3*5-1=839

9*100-(4+5+1+8)=882

10*100/2+3(3+5)=524
by Top Rated User (1.2m points)

Related questions

2 answers
2 answers
1 answer
asked Nov 9, 2012 in order of operations by anonymous | 773 views
1 answer
1 answer
1 answer
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,285 answers
2,420 comments
734,711 users