how do you get 397 suing the numbers 7,4,2,10,6, and 8 using the basic operations

Question

using three basic operations  + , - and X without using a number twice?

how do  you get 385 using  the numbers 7,4,2,10,6, and 8

and 397 using 8,100,50,6,8 and 5 same rules

and 148 using 50,7,7,1,4 and 3

and 839 using 1,75,3,4,5 and 7

and 882 using 5,4,100,9,1 and 8

and 524 using 10,3,100,3,2 and 5

Answer 1

-7+4+(2*10)^-(6-8)=397

7(6-8/4^2)*10=385

8(100-50)-(6+5-8)=397

50(4-1)+7/7-3=148

75(7+4)+3*5-1=839

9*100-(4+5+1+8)=882

10*100/2+3(3+5)=524