determine the area below f(x) = 8x - 2x^2 and above the axis
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1 Answer

 

Area=∫ydx=∫(8x-2x²)dx.

To find the limits of integration solve 8x-2x²=0=2x(4-x).

So limits are [0,4].

Area=[4x²-2x³/3]⁴₀=64-128/3=64/3 sq units.

by Top Rated User (1.2m points)

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