Solve y=(e^-x)(lnx)

Question

I didn't understand how to solve it.

Answer 1

Solve y=(e^-x)(lnx)

When asked for the solution to a function, this means find the value of x in the expression (on the rhs) that makes y (the lhs) equal to zero.

We are being asked to solve y = e^(-x)*ln(x) = 0, or

e^(-x)*ln(x) = 0

By observation we can see that when x = 1, ln(x) = 0 (because ln(1) = 0)

Answer: the solution is x = 1