If 2^100 - 2^192 x31 + 2^n is perfect square find n

Question

perfect square trinomial

Answer 1

I dout yu kan duit

2^100=1, 267, 650, 600, 228, 229, 401, 496, 703,205,376

2^192=6, 277, 101, 735, 386, 680,763....58 digits

then yu multipli bi 31????

then subtrakt this from a number with just 31 digits....yu get very big negativ number

then raez ntu (dont no) power

n gotta be very big just tu ofset the big negativ number from first 2 terms

like yu mite need 2^555555

yu gonna tri all sorts av possabel values for n????