Problem: find the value of n, such that 13^2 + n and n +13^2 are perfect square
find the value of n, such that 13^2 + n and n +13^2 are perfect square
In the first place, (13^2 + n) and (n + 13^2) are exactly the same number,
given any value of n.
13^2 = 169
We can pick any other perfect square and calculate n as the difference
between the two.
14^2 = 196
n = 196 - 169 = 27
(13^2 + n) = (169 + 27) = 196, which is 14^2
10^2 = 100
n = 100 - 169 = -69
(13^2 + (-69)) = 169 - 69 = 100, which is 1^2
There are an infinite number of values for n.