Find the value of n such that the expression is a perfect square trinomial
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1 Answer

??????????? tri-no-mael ??????????

me assume that stuf shood be

x^2 -(2/6)x+n=0

or x^2 -(1/3)x+n=0

tu get (x-sumthun)^2, yu need [x- (1/6)]^2

so n=(1/6)^2=1/36
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