I need to know how to find the points of a quadratic formula and graph it, then find the transformed graph.
in Algebra 2 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

The basic form is what you could call the shape of the quadratic. All quadratics look like U or an inverted U, without reference to the spread of the arms of the U or where it sits in the reference frame. They’re all parabolas.

The basic form is in an “obvious” position and is an upright U. The most obvious position is a seat at the origin (0,0), which would be the lowest point of the U. The equation is y=x².

The basic form is sometimes called the “parent” and its transformations are its “children”. Transformations can be a “seat” shift. The seat is called the vertex, and it can be shifted up, down, left or right. It can also be dilated—magnified or reduced—and reflected (turned upside down). So the shift transformation moves the vertex from (0,0) to some other coordinate which is often represented by (h,k), displacement of x by the amount h and displacement of y by the amount k. The dilation factor is usually represented by a, which can be positive or negative. Negative values produce an inverted U shape, or reflection of the basic shape. So a transformed parabola has the equation: y-k=a(x-h)². When we expand this we get y=ax²-2ahx+h²+k. That’s the quadratic. The constant in a quadratic y=ax²+bx+c is equal to h²+k and b=-2ah, so it’s possible to work out a, h and k from the coefficients in the quadratic. Knowing the vertex and y intercept (= constant c or h²+k) helps to plot the parabola. The x intercepts (if they exist) are the zeroes of the quadratic. Not all parabolas will have x intercepts, but they all have a y intercept.

(Parabolas lying on their side have the basic form x=y².)

by Top Rated User (1.2m points)

Related questions

1 answer
1 answer
asked Mar 29, 2012 in Algebra 1 Answers by anonymous | 1.7k views
1 answer
asked Nov 18, 2011 in Algebra 2 Answers by anonymous | 1.1k views
1 answer
1 answer
asked Mar 26, 2012 in Algebra 1 Answers by anonymous | 1.8k views
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
732,178 users