divide 3x^3 +9x^2 -21z -36 in to 3 x+12

Question

how do i solve

3x^3 +9x^2 -21z -36 divided by 3 x+12

Answer 1

There's a common factor 3 which cancels out during the division, so we can start by dividing the dividend and divisor by 3: (x³+3x²-7x-12)/(x+4).

Use synthetic division:

-4 | 1  3 -7  -12

      1 -4  4 | 12

      1 -1 -3 |   0 remainder

Quotient=x²-x-3.