How do I find the inverse of this equation
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Let y=(x³-4)/(x³-3), y(x³-3)=x³-4, yx³-3y=x³-4, yx³-x³=3y-4, x³=(3y-4)/(y-1), x=∛((3y-4)/(y-1))=f⁻¹(y).


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