the answer given is inverse function of f = ( 1+ sq root of (9+4x)) divide 2
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given x^2-x-2=y then x=y^2 - y - 2 y^2 - y -(2+x)=0 from the general formula for quadratic eqns y = {1+ sqrt[1+4(2+x)]} /2 f^-1(x) = {1+sqrt(9+4x)}/2
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