work out the size of the smallest angle of the quadrilateral

Question

part a)

the sizes of the angles, in degrees, of the quadrilateral are:

x+10

2x

x+90

x+20

use this information to write down an equation in terms of x.

Answer: x+10+2x+x+90(x+20)=360

PART B)

use your answer to part (A) to work out the size of the smallest angle of the quadrilateral.

how do i answer this and explain the reasons why you did what you did.

thanks

:)

 

Answer 1

(A) The sum of the angles is 5x+120=360, 5x=240, x=240/5=48°. (The angles of a quadrilateral must add up to 360°.)

(B) The angles are: x+10=48+10=58, 2x=2×48=96, x+90=138, x+20=68 degrees. The smallest angle is 58°.