v(x)=x3-13x+12

Question

help me with this problem now!

Answer 1

v(x)=x³-13x+12 has x=1 as a zero because v(1)=1-13+12=0. We can divide by this zero using synthetic division:

1| 1 0 -13    12

    1 1    1 | -12

    1 1 -12 |   0 = x²+x-12 = (x+4)(x-3).

So the zeroes of v(x) are 1, -4 and 3 (that is, v(1)=v(-4)=v(3)=0).

The question doesn't ask a specific question, but I guess this solution is probably what's expected.