how to find the root of y=2x^+x+6
in Algebra 1 Answers by Level 1 User (140 points)

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If you meant 2x2+x+6 as the quadratic, there are no real roots or zeroes, because the only roots are complex, and I don't think Algebra 1 curriculum includes complex numbers.

If you meant 2x2+x-6 then this is the same as (2x-3)(x+2), and the zeroes are x=3/2 and -2.

If this question has been wrongly categorised, and you understand complex numbers then one way of solving the quadratic (finding its zeroes or roots) is:

2x2+x+6=0,

2x2+x=-6,

x2+½x=-3,

x2+½x+1/16=-3+1/16=-47/16,

(x+¼)2=-47/16,

x+¼=±¼√(-47)=±¼i√47,

x=-¼±¼i√47. (i is the imaginary √(-1).)

(Just as "ordinary" numbers can be represented on a number line, which is one-dimensional, complex numbers are treated as if they belong to a number plane (two dimensions). The second dimension is called the imaginary dimension, while the first dimension is the real dimension of ordinary numbers.)

by Top Rated User (1.2m points)

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