It belongs to numerical method problem
asked Dec 4, 2016 in Other Math Topics by anonymous

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1 Answer

In this method we use the derivative f'(x)=3x^2-2 and apply the iteration:

x1=x0-f(0)/f'(0) initially. Put x=0 initially: -(-5/-2)=2.5 is x1.

Plug in x1: x2=2.164...-f(2.164...)/f'(2.164...)=2.097...

x3=2.094555232, x gets closer to 2.094551482 fairly rapidly.
answered Dec 4, 2016 by Rod Top Rated User (486,900 points)
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