A(x)=(100e0.01x)2 is the cross-section area, so A(x)=10000e0.02x. Volume of a thin disc with this cross-section area is 10000e0.02xdx, where dx is the infinitesimal thickness of the disc. So V=∫A(x)dx=10000∫010e0.02xdx=10000[e0.02x/0.02]010.
V=500000(e0.2-1)=500000(1.2214-1)=110,700 cubic units approximately.