an arc lies in position on the unit circle. find the coordinates of the terminal point of the arc if the arc has lenght  pi
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The circumference of the unit circle is 2π so π is the length of a semicircular arc.

If the semicircle starts at (-1,0) its terminal point is (1,0).

If the semicircle starts at (0,1) its terminal point is (0,-1).

The equation of the unit circle is x2+y2=1.

The line y=ax is the equation of its diameters where a is any number. The diameter intersects the circle when:

x2+a2x2=1, x2=1/(1+a2), x=±√(1/(1+a2))

so 1/(1+a2)+y2=1, y2=1-1/(1+a2)=a2/(1+a2), y=±a/√(1+a2).

If a=1, x=y=±1/√2=±√2/2, so the arc has endpoints (√2/2,√2/2) and (-√2/2,-√2/2).

If a=-1, x=±√2/2, y=∓√2/2, endpoints are (√2/2,-√2/2) and (-√2/2,√2/2).

In general then, the endpoints are:

(√(1/(1+a2)),a/√(1+a2)) and (-√(1/(1+a2)),-a/√(1+a2)).

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