a curve has d2y/dx2=18sin3x and a stationary point at (pi/6,-2). find the equation of the curve
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d^2y/dx^2 = 18sinx................... let dy/dx = p

⇒d^2y/dx^2 = dp/dx

...dp/dx = 18sin3x....... dp = 18sin3x.dx

⇒p = -54cos3x + c............... but when x = pi/6 , y = -2

.: c = 27sqrt(2)

again, from...........p = -54cos3x + c

⇒dy/dx = -54cos3x + 27sqrt(2)................⇒dy = {-54cos3x + 27sqrt(2)}dx

.: y = -162sin3x + 27xsqrt(2) + A

Again... when x = pi/6 , y = -2

⇒A = sqrt(2){81 - 27.pi/6}  - 2

.: y = -162sin3x + 27sqrt(2) + sqrt(2){81 - 27.pi/6} - 2..............[required equation]

by Level 3 User (4.0k points)

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