how to find gradient of trigonometric curves

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"gradient"=slope=dy/dx

d(sine(x))=kosine

3*time=3*kosine(x), evaluate at x=0...3

d/dx(tan(x))=sekant^2, but sekant=(1/kosine), so yu have 1/kosine(0)^2=1^2=1

anser...3+1=4
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