solve tanx(cscx+2)=0

solve the following open sentence for 0<x<360 to the nearest degree. write answers in radians as well.
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Either tan(x)=0, so x=180° for 0°<x<360°; or csc(x)+2=0, that is, csc(x)=-2, sin(x)=-½.

When x=30 sin(x)=½. Sine is negative in quadrants 3 and 4 (between 180° and 360°).

x=180+30=210° and 360-30=330°.

SOLUTION: x=180, 210 or 330 degrees.

by Top Rated User (1.2m points)

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