We need to find the minimum and maximum of R.
Minimum=4.5-0.05+6.5-0.05=4.45+6.45=10.90 (same as 4.5+6.5-0.10);
Maximum=4.55+6.55=11.10 (same as 4.5+6.5+0.10).
Therefore 10.90≤R≤11.10 or R=11.0±0.1.
You could also use the RMS of the two errors ε=√(0.05)2+(0.05)2)=0.05√2=0.07 approx., so R=11.00±0.07, which is the same as 10.93≤R≤11.07.