Solve f(x)=e^2x for the 5th derivative

Question

This is the 5th derivative using e and I also need a general rule for finding it.

Answer 1

f'=2e^2x; f''=4e^2x;... so the 5th derivative is 2^5e^2x=32e^2x.

Answer 2

if we defferentiate e power  2x....we have , since da power is 2x and da derivative of 2x is 2 ,,,,,,we multply 2 by da original equation we have F'x)=2e^2x..again we do for the 2nd derivative we have F''X)=4e^2x  ...about the fith derivative we have ,,,,F'''''X)=32e^2x

Answer 3

e^2x .fifth derivative is 2^5 =32 .32 wil be the coeffficient i.e 32e^2x