Given y=sin x/sec(3x+1), find dy/dx

It is a derivative question using Chain Rule.
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1 Answer

Using the chain rule for quotients we get

dy/dx = [cos(x)*sec(3x+1) - 3*sin(x)*sec(3x+1)*tan(3x+1)] / sec^2(3x+1)

Factoring out sec(3x+1) this simplifies to

dy/dx = [cos(x) - 3*sin(x)*tan(3x+1)] / sec(3x+1)

done!
by Level 2 User (1.7k points)

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