Use chain rule to find the following derivative:

((t-3)^2) / ((t+1)^1/2)
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f(t) = (t - 3)^2 / (t + 1)^1/2 = g(t) / h(t)

Using chain rule for quotients which is

f'(t) = g'(t) * h(t) - g(t) * h'(t) / h(t)^2

we get

f'(t) = [2*(t - 3)*(t +1)^1/2 - (t - 3)^2*(1/2*(t + 1)^-1/2)] / (t + 1)

done!
by Level 2 User (1.7k points)

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