what is normal curve area, to the nearest whole percent, between z = -0.38 and z = +1.5

The question is about z scores and normal curve area
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The percentage of normal area for z=1.5 is 0.9332 and for z=-0.38 is 1-0.6480=0.3520 (where 0.6480 is the value for z=+0.38), so the difference is 0.9332-0.3520=0.5812 or 58% to the nearest percent.

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