Given that z is a standard normal variable, find z for each situation. The area between -z and z is .2052
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If the area between -z and z is 0.2052, then the area between -z and 0 is 0.1026, which means the area below -z is 0.5 - 0.1026 = 0.3974.

What is the value of z such that p(Z<-z) = 0.3974 ?

Using the z table here ( http://www.stat.ufl.edu/~athienit/Tables/Ztable.pdf ):

-z = -0.26

z = 0.26

by Level 13 User (103k points)

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