Number of permutations=1122 (twice the number of combinations).
Let's label all the elements of the set using the numbers 1 to 34.
So we have combinations (1,2), (1,3), (1,4), ..., (1,34) (33 of these),
and (2,3), (2,4), (2,5), ..., (2,34) (32 of these),
...
(32,33), (32,34) (2 of these),
(33,34).
Therefore the total number of combinations is 1+2+3+...+31+32+33.
Take these in pairs (1+33), (2+32), (3+31), ... each pair sums to 34.
Total sum=34×33/2=17×33=561.
So number of permutations=2×561=1122.