A lawn roller is 150 cm long and has a diameter of 70 cm. to level a playground, it takes 750 complete revolutions. Determine the cost of levelling the playground at the rate of $2.00 per square metre.
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The area rolled in one revolution of the roller is equal to the circumference of the roller multiplied by its length=70(pi)*150=10500(pi)sq cm=1.05 sq m. In other words, the surface area of a cylinder of diameter 70 and length 150. 750 revs=750*1.05 sq m=787.5 sq m. The cost of levelling is 787.5*2=$1575.

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