3+2i/3-2i=

3+2i/3-2i=
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1 Answer

3+2i/3-2i= ///////// multiple 3+2i and 3-2i by 3+2i

(3+2i)(3+2i) /(3-2i)(3+2i) =

(9+12i+4(i^2))/(9-4(i^2))= ///////// i^ 2 =-1

 (9+12i-4)/(9+4)=

(5+12i)/13 final answer
by Level 1 User (620 points)

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