for the function f(x)1/8x the different quotient
in Algebra 2 Answers by Level 1 User (120 points)

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If f(x)=⅛x, then f(x+h)=⅛(x+h)=⅛x+⅛h; (f(x+h)-f(x))/h is the difference quotient:

(⅛x+⅛h-⅛x)/h=⅛h/h=⅛, so the difference quotient is ⅛.

If f(x)=1/(8x), then f(x+h)=1/(8x+8h).

(f(x+h)-f(x))/h=[1/(8x+8h)-1/(8x)]/h=

(8x-(8x+8h))/(8xh(8x+8h))=

-8h/(64x2h+64xh2)= (divide top and bottom by 8h)

-1/(8x2+8xh).

As h→0, this becomes -1/(8x2), the derivative of f(x)=1/(8x).

by Top Rated User (1.2m points)

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