((27a^3b^-2c^-2)/(3a^2b^-4c^-2))

to divide ((27a^3b^-2c^-2)/(3a^2b^-4c^-2))
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1 Answer

(27a3b-2c-2)/(3a2b-4c-2)=

(27/3)(a3-2)(b-2-(-4))(c-2-(-2))=(9)(a1)(b4-2)(c-2+2)=

9ab2c0=

9ab2.

by Top Rated User (1.2m points)

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