log[8](t+10) - log[8](t-1) = log[8]12

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1 Answer

log8(t+10)-log8(t-1)=log8(12),

log8[(t+10)/(t-1)]=log8(12),

(t+10)/(t-1)=12,

t+10=12t-12,

22=11t, t=2.

by Top Rated User (1.2m points)

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