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I read this as (3-3n)/(7(.9)n+8).

The numerator diverges to a large negative number as n increases. (.9)n gets smaller as n increases so the denominator converges to 8 because (.9)n→0.

Since the denominator converges to a constant while the numerator diverges quite fast, the quotient also diverges.

Therefore the quotient does not converge, but diverges negatively.

If, however, n decreases (goes negative) then the numerator converges to 3 as n becomes more negative, while the denominator diverges so the quotient converges to zero.

by Top Rated User (1.2m points)

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