I read this as (3-3n)/(7(.9)n+8).
The numerator diverges to a large negative number as n increases. (.9)n gets smaller as n increases so the denominator converges to 8 because (.9)n→0.
Since the denominator converges to a constant while the numerator diverges quite fast, the quotient also diverges.
Therefore the quotient does not converge, but diverges negatively.
If, however, n decreases (goes negative) then the numerator converges to 3 as n becomes more negative, while the denominator diverges so the quotient converges to zero.