how do you solve 5(4z+6)-2(z-4)=7z(z+4)-z(7z-2)-48

it has to be solved using the Equations with Polynomials on Both sides

Ive tried solving it and i cant so best of luck
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1 Answer

Expand the parentheses:

20z+30-2z+8=7z2+28z-7z2+2z-48,

18z+38=30z-48,

78=12z,

13=2z, z=13/2.

by Top Rated User (1.2m points)

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